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1 02 14 LE sia DIS 0 1 > 57 329 5636 es SSC 559 ST CF HY NO 6430 631 600 4 17 27 672 SOS 9 Thirty-three percent of all Americans drink bottled water more than once a week (Natural resources Defense Council, December 4, 2015) Suppose you have been hired by the Natural Resources Defence Council to investigate bottled water consumption in St. Paul. You plan to select a sample of St. Paulites to estimate the proportion who drink bottled water more than once a week. Assume the population proportion of St. Paulites who drink bottled water more than once a week is 0.33, the same as the overall proportion of Americans who drink bottled water more than once a week. Use z-table. a. Suppose you select a sample of 540 St.Paulites. Show the sampling distribution of p (to 4 decimals). EP) .33 ар 0.0202 b. Based upon a sample of 540 St. Paulites, what is the probability that the sample proportion will be within 0.02 of the population proportion (to 4 decimals). probability c. Suppose you select a sample of 270 St. Paulites. Show the sampling distribution of (to 4 decimals), E(P) 0.33 0.0286 d. Based upon a smaller sample of only 270 St. Paulites, what is the probability that the sample proportion will be within 0.02 of the population proportion (to 4 decimals), .9967 probability = e. As measured by the increase in probability, how much do you gain in precision by taking the larger sample in parts (a) and (b) rather than the smaller sample in parts (c) and (d)? 3 Reduced by Have gain in precision by increasing the sample. 1
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9Thirty-three percent of all Americans drink bottled water more than once a week (Natural resources Defense Council, Decembera. Suppose you select a sample of 540 St.Paulites. Show the sampling distribution of p (to 4 decimals).
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ар 0.0202
b.

1 Approved Answer

Jones G
4 Ratings (9 Votes)
a. Sampling Distribution of Sample Proportion (p) for a Sample of 540 St. Paulites: Given the population proportion (P) is 0.33, and the sample size (n) is 540, we can calculate the standard error (SE) using the formula: SE = sqrt[P(1 - P) / n] SE = sqrt[0.33 * (1 - 0.33) / 540] SE = sqrt[0.2211 / 540] SE ˜ 0.0202 (rounded to 4 decimals) So, the standard error (SE) is approximately 0.0202. b. Probability that the Sample...

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