In ∆ABC and ∆DEF, it is being given that: AB = 5 cm, BC = 4 cm and CA = 4.2 cm; DE = 10 cm, EF = 8 cm and FD = 8.4 cm. If AL ⊥ BC and DM ⊥ EF, find AL : DM.

If $\Delta ABC$ $\cong$ $\Delta DEF$ by S.S.S. congruence, then which of the following options is correct?

$In\Delta ABCand\Delta DEF,\text{it is given that AB = DE and BC = EF. In order that}\Delta ABC\cong \Delta DEF,\text{we must have}\left(a\right)\angle A=\angle D\left(b\right)\angle B=\angle E\left(c\right)\angle C=\angle F\left(d\right)\text{none of these}$

If $\Delta ABC$ $\cong$ $\Delta DEF$ by S.S.S. congruence, then, which of the following options is correct?